Topic · 16 games

Electric circuits: voltage, current, and resistance

A cell lifts charge to a higher potential, and the charge flows back down through the circuit. A voltage is always measured between two points: V = V_red − V_black.

Games in this topic

16 games

PLAY NOW · 102

Battery Stack: Adding Up Voltages

Cells in a row add their voltages, a flipped cell takes its voltage away, and cells side by side give the voltage of one. A battery gives every coulomb it moves V joules: W = Q·V. Stack, flip, line up, power a lamp, and count cells.

VoltageCells in series
Play Battery Stack
Cells in a row
V = V₁ + V₂ + …
Energy per charge
W = Q·V

PLAY NOW · 103

Voltmeter Walk: Voltage Between Two Points

A voltmeter reads the potential at its red probe minus the potential at its black probe: V = V_red − V_black. Swap the probes, try an open switch and a plain wire, find the voltage at a junction, and set two cells against each other.

VoltageUsing a voltmeter
Play Voltmeter Walk
A voltmeter reads
V = V_red − V_black
Down a resistor
ΔV = I·R

PLAY NOW · 104

Charge Gate: Current Is Charge per Second

A current is the charge that passes a cut across the wire each second: I = Q ÷ t, and one ampere is one coulomb a second, about 6 × 10¹⁸ electrons. Count the charge at the gate, turn minutes and hours into seconds, and time a slow current.

CurrentCharge and time
Play Charge Gate
Current is
I = Q ÷ t
One ampere
1 A = 1 C/s

PLAY NOW · 105

Snail Electrons: Slow Drift, Fast Signal

Electrons jitter at about a million metres a second but drift along a wire like snails: I = n·e·A·v_d gives under a tenth of a millimetre a second for 1 A in copper. Yet a lamp lights at once, because the signal runs along the wire at 2 × 10⁸ m/s.

CurrentDrift speed
Play Snail Electrons
Current from drift
I = n·e·A·v_d
The signal
v ≈ 2 × 10⁸ m/s

PLAY NOW · 106

Wire Stretcher: Length and Thickness Set Resistance

A wire's resistance grows with its length and falls with its cross-section: R = ρ·L ÷ A. Twice the length doubles R, twice the diameter gives a quarter, and stretching a wire to twice its length makes R four times larger. Unroll, stretch, and cut a coil to size.

ResistanceResistivity
Play Wire Stretcher
Resistance of a wire
R = ρ·L ÷ A
Round wire
A = π·d² ÷ 4

PLAY NOW · 107

Hot Filament: Resistance Rises with Temperature

A metal resists more as it heats: R = R₀·(1 + α·(T − T₀)). A lamp filament at 2500 °C has twelve times its cold resistance, so a lamp takes a surge of current when switched on, and a platinum wire makes a thermometer. Heat, glow, and read the temperature.

ResistanceTemperature
Play Hot Filament
Hot resistance
R = R₀·(1 + α·ΔT)
Platinum sensor
R = 100 Ω·(1 + 0.00385·T)

PLAY NOW · 108

Ohm's Law Lab: Current, Voltage, and Resistance

For a fixed resistor, the current grows in proportion to the voltage: V = I·R, a straight line through the origin on an I–V graph. Find a current, a resistance, or a voltage from the other two, read a line, and pick the resistor that keeps an LED at 20 mA.

Ohm's lawI–V graph
Play Ohm's Law Lab
Ohm's law
V = I·R
Rearranged
I = V ÷ R, R = V ÷ I

PLAY NOW · 109

Fuse Test: Ohm's Law Meets Its Limits

I = V ÷ R sets every current here, and a fuse melts the moment the current reaches its rating. Find a kettle's current, the smallest resistance a fuse survives, why a fuse does not protect a person, the most voltage a resistor can take, and the huge current of a short circuit.

Ohm's lawFuses
Play Fuse Test
Current
I = V ÷ R
The fuse melts when
I ≥ I_fuse

PLAY NOW · 110

Bulb Chain: One Path for Every Bulb

In a series circuit there is only one path, so the same current flows through every bulb and the resistances add: R = R₁ + R₂ + …. Find the current, the total resistance, one bulb's share of the voltage, why a fourth bulb dims them all, and how many fairy lights the mains needs.

Series circuitsVoltage sharing
Play Bulb Chain
Resistances add
R = R₁ + R₂ + …
Same current
I₁ = I₂ = I₃

PLAY NOW · 111

Voltage Divider: Sharing the Supply

Two resistors in series split the supply in proportion to their resistances: V_out = V·R₂ ÷ (R₁ + R₂). Find an output voltage, design a divider for 5 V, read a light sensor and a thermistor, and find the voltage partway down a chain of three.

Voltage dividersSensors
Play Voltage Divider
Output
V_out = V·R₂ ÷ (R₁ + R₂)
Shares in proportion
V₁ ÷ V₂ = R₁ ÷ R₂

PLAY NOW · 112

Room Wiring: Every Branch Gets the Full Voltage

Parallel branches each get the full voltage: the currents add and the combined resistance falls, 1/R = 1/R₁ + 1/R₂ + …. Find a combined resistance and a main current, see why the other lamps stay lit when one is unplugged, choose a resistor, and count the lamps a breaker allows.

Parallel circuitsHouse wiring
Play Room Wiring
Resistance
1/R = 1/R₁ + 1/R₂ + …
Main current
I = I₁ + I₂ + …

PLAY NOW · 113

Current Splitter: What Flows In Flows Out

Current is never used up at a junction: what flows in flows out, I = I₁ + I₂ + …. Branches in parallel share one voltage, so the smaller resistance takes the larger share. Find a missing current, divide a current, add the branches, see why a new branch leaves the old one alone, and design a shunt.

Kirchhoff's current lawCurrent division
Play Current Splitter
At a junction
I_in = I_out
Same voltage
I₁·R₁ = I₂·R₂

PLAY NOW · 114

Bulb Brightness: Power, Not the Label

Power is the rate a bulb turns electrical energy into light and heat: P = V·I = I²·R = V² ÷ R. Its rating only fixes its resistance. Find a power, a bulb's resistance, what two bulbs in series give, why the 60 W bulb wins when paired with a 100 W one, and what half the voltage does.

Electrical powerRatings
Play Bulb Brightness
Power
P = V·I = I²·R = V² ÷ R
From a rating
R = V² ÷ P

PLAY NOW · 115

Power Line: Why the Wires Run at High Voltage

The same power can be sent as a large current at low voltage or a small current at high voltage, and the line's heating grows with the current squared: P_loss = I²·R. Find the loss at two voltages, design a line that loses 1%, heat a line, and size a heater at the house.

Electrical powerTransmission lines
Play Power Line
Line current
I = P ÷ V
Line loss
P_loss = I²·R

PLAY NOW · 116

Kettle Race: Energy Is Power Times Time

The energy a kettle supplies is its power times the time, E = P·t, and the water needs m·c·ΔT to warm up. Race a kettle against your predicted time, find the energy it uses, see what heat losses do, choose a power, and see why a kettle abroad takes four times as long.

Electrical energyHeating water
Play Kettle Race
Energy
E = P·t
Heating water
E = m·c·ΔT

PLAY NOW · 117

Energy Meter: The Kilowatt-Hour Is an Energy

The kilowatt-hour on an energy bill is not a power but an energy: 1 kW for 1 h, or 3600 kJ. Find a lamp's energy, what standby costs in a month, a power bank in kilojoules, what an LED saves over 1000 hours, and how much energy a phone battery holds.

Electrical energyKilowatt-hours
Play Energy Meter
Energy
E (kWh) = P (kW) · t (h)
Conversions
1 kWh = 3600 kJ

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