Satellite Launch: Universal Gravitation

An educational simulation game. Predict how hard Earth pulls on a satellite, how that pull fades with distance, and the speed or radius that keeps it in orbit, then launch and watch.

Universal gravitationOrbits

ORBIT VIEW

Pull on a satellite

Ready
Enable JavaScript to launch the satellite. The instructions and worked example remain readable.
Velocity vGravity gPath and targetYour prediction
Universal gravitationF = G·M·m ÷ r²

Time

0.0 min

t

Distance from Earth's centre

— km

r = R + h

Pull of gravity

— N

F = G·M·m ÷ r²

Acceleration due to gravity

— m/s²

g = G·M ÷ r²

Speed

— m/s

|v|

Predict before you launch

Type your answer to set up the launch. Launch stays off until there is an answer.

Predict the launch before you start it.

Mission score—

A right answer, within 2%, earns 100 points. Getting it right on the first launch adds 50. A launch counts as soon as it starts.

✓ Right answer① First try

How to play Satellite Launch

  1. Choose a launch and read the satellite's mass, its height, or the period on the card. G, M, and R are under the list.
  2. Use F = G·M·m ÷ r² or g = G·M ÷ r², always with r = R + h measured from Earth's centre, in metres.
  3. Type your answer and press Launch. A force or gravity answer is checked against the measurement; a speed launches the satellite; a radius places the geostationary orbit.
  4. After each launch, read the graph: at twice the distance from the centre, the pull is a quarter as strong.

What is the law of universal gravitation?

Newton's law of universal gravitation says that any two masses attract each other with a force F = G·M·m ÷ r², where r is the distance between their centres and G = 6.674 × 10⁻¹¹ N·m²/kg². The force grows with each mass and falls with the square of the distance: twice as far, a quarter of the force. Dividing by m gives the acceleration due to gravity, g = G·M ÷ r², which is the same for every object at that distance. A satellite in orbit is falling all the time, but it moves sideways fast enough that the ground curves away beneath it. For a circular orbit, gravity supplies exactly the centripetal force: G·M·m ÷ r² = m·v² ÷ r, so v = √(G·M ÷ r).

A focused learning model

Earth and the satellite are point masses, Earth stays fixed at the centre, and there is no air drag or pull from the Moon or the Sun. The path is the exact ellipse, circle, or hyperbola of the launch, timed with Kepler's equation. Hitting the ground, leaving the view, and completing an orbit are found exactly. Earth's rotation is shown only in the geostationary mission. Orbits are drawn to scale and played faster, by the factor shown on the canvas.

Changing language keeps your launch, answer, attempts, and run.